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Fix Plymouth passphrase prompt in initramfs script

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Entering the ZFS encryption passphrase under Plymouth wasn't working
because in the ZFS initrd script, Plymouth was calling zfs via
"--command", which wasn't passing through the filesystem argument to
zfs load-key properly (it was passing through the single quotes around
the filesystem name intended to handle spaces literally,
which zfs load-key couldn't understand).

Reviewed-by: Richard Laager <rlaager@wiktel.com>
Reviewed-by: Garrett Fields <ghfields@gmail.com>
Signed-off-by: Richard Allen <belperite@gmail.com>
Issue #9193
Closes #9202
This commit is contained in:
Richard Allen 2019-08-27 21:44:02 +01:00 committed by Brian Behlendorf
parent e7a2fa70c3
commit f335b8ffe1
1 changed files with 8 additions and 8 deletions
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16
contrib/initramfs/scripts/zfs.in
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@ -411,29 +411,29 @@ decrypt_fs()
# Determine dataset that holds key for root dataset
ENCRYPTIONROOT=$(${ZFS} get -H -o value encryptionroot "${fs}")
DECRYPT_CMD="${ZFS} load-key '${ENCRYPTIONROOT}'"
# If root dataset is encrypted...
if ! [ "${ENCRYPTIONROOT}" = "-" ]; then
TRY_COUNT=3
# Prompt with plymouth, if active
if [ -e /bin/plymouth ] && /bin/plymouth --ping 2>/dev/null; then
plymouth ask-for-password --prompt "Encrypted ZFS password for ${ENCRYPTIONROOT}" \
--number-of-tries="3" \
--command="${DECRYPT_CMD}"
while [ $TRY_COUNT -gt 0 ]; do
plymouth ask-for-password --prompt "Encrypted ZFS password for ${ENCRYPTIONROOT}" | \
$ZFS load-key "${ENCRYPTIONROOT}" && break
TRY_COUNT=$((TRY_COUNT - 1))
done
# Prompt with systemd, if active
elif [ -e /run/systemd/system ]; then
TRY_COUNT=3
while [ $TRY_COUNT -gt 0 ]; do
systemd-ask-password "Encrypted ZFS password for ${ENCRYPTIONROOT}" --no-tty | \
${DECRYPT_CMD} && break
$ZFS load-key "${ENCRYPTIONROOT}" && break
TRY_COUNT=$((TRY_COUNT - 1))
done
# Prompt with ZFS tty, otherwise
else
eval "${DECRYPT_CMD}"
$ZFS load-key "${ENCRYPTIONROOT}"
fi
fi
fi