zdb: zero-pad checksum output

The leading zeroes are part of the checksum so we should show them.

Reviewed-by: Richard Yao <richard.yao@alumni.stonybrook.edu>
Reviewed-by: Brian Behlendorf <behlendorf1@llnl.gov>
Signed-off-by: Rob Norris <robn@despairlabs.com>
Closes #14464
This commit is contained in:
Rob N ★ 2023-02-08 08:48:22 +11:00 committed by GitHub
parent eb823cbc76
commit ac7648179c
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@ -2377,7 +2377,8 @@ snprintf_blkptr_compact(char *blkbuf, size_t buflen, const blkptr_t *bp,
(void) snprintf(blkbuf + strlen(blkbuf),
buflen - strlen(blkbuf), " %s", "FREE");
(void) snprintf(blkbuf + strlen(blkbuf),
buflen - strlen(blkbuf), " cksum=%llx:%llx:%llx:%llx",
buflen - strlen(blkbuf),
" cksum=%016llx:%016llx:%016llx:%016llx",
(u_longlong_t)bp->blk_cksum.zc_word[0],
(u_longlong_t)bp->blk_cksum.zc_word[1],
(u_longlong_t)bp->blk_cksum.zc_word[2],
@ -8383,7 +8384,9 @@ zdb_read_block(char *thing, spa_t *spa)
DVA_GET_OFFSET(&bp->blk_dva[0]);
ck_zio->io_bp = bp;
zio_checksum_compute(ck_zio, ck, pabd, lsize);
printf("%12s\tcksum=%llx:%llx:%llx:%llx\n",
printf(
"%12s\t"
"cksum=%016llx:%016llx:%016llx:%016llx\n",
zio_checksum_table[ck].ci_name,
(u_longlong_t)bp->blk_cksum.zc_word[0],
(u_longlong_t)bp->blk_cksum.zc_word[1],