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zdb: zero-pad checksum output
The leading zeroes are part of the checksum so we should show them. Reviewed-by: Richard Yao <richard.yao@alumni.stonybrook.edu> Reviewed-by: Brian Behlendorf <behlendorf1@llnl.gov> Signed-off-by: Rob Norris <robn@despairlabs.com> Closes #14464
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@ -2377,7 +2377,8 @@ snprintf_blkptr_compact(char *blkbuf, size_t buflen, const blkptr_t *bp,
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(void) snprintf(blkbuf + strlen(blkbuf),
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buflen - strlen(blkbuf), " %s", "FREE");
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(void) snprintf(blkbuf + strlen(blkbuf),
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buflen - strlen(blkbuf), " cksum=%llx:%llx:%llx:%llx",
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buflen - strlen(blkbuf),
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" cksum=%016llx:%016llx:%016llx:%016llx",
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(u_longlong_t)bp->blk_cksum.zc_word[0],
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(u_longlong_t)bp->blk_cksum.zc_word[1],
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(u_longlong_t)bp->blk_cksum.zc_word[2],
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@ -8383,7 +8384,9 @@ zdb_read_block(char *thing, spa_t *spa)
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DVA_GET_OFFSET(&bp->blk_dva[0]);
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ck_zio->io_bp = bp;
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zio_checksum_compute(ck_zio, ck, pabd, lsize);
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printf("%12s\tcksum=%llx:%llx:%llx:%llx\n",
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printf(
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"%12s\t"
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"cksum=%016llx:%016llx:%016llx:%016llx\n",
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zio_checksum_table[ck].ci_name,
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(u_longlong_t)bp->blk_cksum.zc_word[0],
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(u_longlong_t)bp->blk_cksum.zc_word[1],
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