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FreeBSD: Don't require zeroing new locks before init
This has not shown to be of use enough to justify the inconvenience. Reviewed-by: Matt Macy <mmacy@FreeBSD.org> Reviewed-by: Alexander Motin <mav@FreeBSD.org> Reviewed-by: Allan Jude <allanjude@freebsd.org> Signed-off-by: Ryan Moeller <ryan@iXsystems.com> Closes #10449
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@ -39,7 +39,7 @@ typedef struct sx kmutex_t;
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#include <sys/sx.h>
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#include <sys/sx.h>
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typedef enum {
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typedef enum {
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MUTEX_DEFAULT = 6 /* kernel default mutex */
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MUTEX_DEFAULT = 0 /* kernel default mutex */
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} kmutex_type_t;
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} kmutex_type_t;
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#define MUTEX_HELD(x) (mutex_owned(x))
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#define MUTEX_HELD(x) (mutex_owned(x))
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@ -53,9 +53,7 @@ typedef enum {
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#define mutex_init(lock, desc, type, arg) do { \
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#define mutex_init(lock, desc, type, arg) do { \
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const char *_name; \
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const char *_name; \
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ASSERT((type) == 0 || (type) == MUTEX_DEFAULT); \
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ASSERT((type) == MUTEX_DEFAULT); \
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KASSERT(((lock)->lock_object.lo_flags & LO_ALLMASK) != \
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LO_EXPECTED, ("lock %s already initialized", #lock)); \
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for (_name = #lock; *_name != '\0'; _name++) { \
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for (_name = #lock; *_name != '\0'; _name++) { \
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if (*_name >= 'a' && *_name <= 'z') \
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if (*_name >= 'a' && *_name <= 'z') \
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break; \
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break; \
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